now my sensor node works fine and i send the following data:

00 12 78 08 01 59 89 80 03 37 60 34 11

First 4 Bytes = resistance NTC1 (127808 Ohm)
Second 4 Bytes = resistance NTC2 (159898 Ohm)
Next 3 Bytes = resistance of fluid (33760 Ohm)
Last 2 Bytes = battery voltage in mV (3411 mV)

And here i must calculate NTC resistance with function ln(x) (logarithmus naturalis) in temperature value. Is there a mathematical function for ln(x) available?
My question is how to convert this data in a human readable format or in a graphical diagram?

In JavaScript, ln(x) is Math.log(x). We’d need more details about the NTCs to get a proper conversion from resistance to temperature. But the following Decoder can be used in the Payload Format in an application in TTN Console to get you started:

/**
* Convert the array of bytes into an unsigned integer, assuming packed
* binary-coded decimal (BCD) with an even number of nibbles, MSB, like
* decoding 0x00127808 to decimal 127808.
*/
function bcdToUint(bytes) {
return bytes.reduce(function(acc, byte) {
return 100*acc + 10*(byte >> 4) + (byte & 0x0F);
}, 0);
}
/**
* Get a temperature given a resistance, assuming an NTC using the
* Steinhart equation. See https://www.espruino.com/Thermistors
*/
function resistanceToTemperature(r) {
// TODO: validate if Steinhart is okay, and adjust coefficients
var a = 0.0012874;
var b = 0.00023573;
var c = 0.000000095052;
var w = Math.log(r);
var temperature = 1 / (a + w*(b + c*w*w)) - 273.15;
// Unary plus operator to cast string result of toFixed to number
return +temperature.toFixed(1);
}
function Decoder(bytes, port) {
var i = 0;
var r1 = bcdToUint(bytes.slice(i, i+=4));
var r2 = bcdToUint(bytes.slice(i, i+=4));
var r3 = bcdToUint(bytes.slice(i, i+=3));
var v = bcdToUint(bytes.slice(i, i+=2));
return {
r1: r1,
r2: r2,
r3: r3,
t1: resistanceToTemperature(r1),
t2: resistanceToTemperature(r2),
t3: resistanceToTemperature(r3),
v: v/1000
};
}

If this is some off-the-shelf device, then please add some details about the brand and type. Future users might need the same answers.