Antenna length for 868 and 433 MHz

End Devices (Nodes) Hardware
5

So for 915 MHz, the measurements would be:

  1. for full wavelength: 299.792.458 / 915.000.000 = 32,76 cm
  2. for half wavelength: 32,76 cm /2 = 16.38 cm
    3( for quarter wavelength: 16.38 cm /2 = 8.19 cm
    Is this correct?

Yes, that is correct.

As for the cable, will any diameter do?

Any 50 ohm cable will do. You choose the diameter according to the physical circumstances, e.g. thin cable inside an enclosure, thicker cable for mounting indoors. Different cable have different cable loss, so for longer ranges you might want to check into that.

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